Partial End release of Bar Element ################################## Beam Behaviour -------------- For beam we have 4 shape functions, namely $N_1$, $N_2$, $M_1$, $M_2$ Also we have 4 conditions for each of these functions: .. code-block::cs |#|condition| $N_1$ |$N_2$ |$M_1$ |$M_2$| |-|--|--|--|--|--| |1|$F(\xi=-1)$|1 |0 |0 |0 |2|$\frac {dF}{d\xi}(\xi=-1)$|0 |0 |1|0 |3|$F(\xi=+1)$| 0 | 1 |0 | 0 |4|$\frac {dF}{d\xi}(\xi=+1)$| 0 | 0 | 0|1 For example for $N_1$ we have four conditions - $N_1(\xi=-1)=1$ - $N_1'(\xi=-1)=0$ - $N_1(\xi=1)=0$ - $N_1'(\xi=1)=0$ Right side is column $N_1$. Now if we have partial release, then appropriated row will be eliminated. For example if $\Delta_{left}$ of left node is released, then the row #1 will be eliminated. For $\theta_{left}$, $\Delta_{right}$ and $\theta_{right}$ the rows 2 to 4 will be eliminated. If we assume order 3 for each shape function, then